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I think having a rigid will change the stiffness on contact and this is what makes the difference.
What is the Istiff on contact card with and without Rigid?
sure i'll try it out.
there are two cases
1. with rigid
2. with out rigid.
geometry is different in both cases but phenomenon is same.
for first case
disp curve is
X Y
0sec 0mm
0.1 sec 20 mm
for second case
X Y
0sec 0mm
0.01 sec 10 mm
my question is will time step result into such elemental behaviour?
sure i'll try it out.
there are two cases
1. with rigid
2. with out rigid.
geometry is different in both cases but phenomenon is same.
for first case
disp curve is
X Y
0sec 0mm
0.1 sec 20 mm
for second case
X Y
0sec 0mm
0.01 sec 10 mm
my question is will time step result into such elemental behaviour?
are you doing an impact analysis or an quasi-static analysis? I think it sholud be a case of quasi static analysis. Surely what you are giving as loading time is too rapid. I suggest you take default value of 0.3 for your loading and check the results.
are you doing an impact analysis or an quasi-static analysis? I think it sholud be a case of quasi static analysis. Surely what you are giving as loading time is too rapid. I suggest you take default value of 0.3 for your loading and check the results.
what is the energy error you are getting for the simulation?
I'll revert on energy plot,
having licencing error, server is down.
Thanks guys for the support.
1.Make changes in property and try using QEPH formulation to aviod hourglass energy.
2. Give your loading gradual to avoid sudden impacts you may consider to give the end time as 0.3.
Apply these changes and check the results. You please go through the previous content for Radioss regarding energy error and troubleshooting techniques.
@Nachiket Kadu @Prakash Pagadala @George P Johnson
I want to check pressing force required to insert ring into hub,
I have simulated 1/4th geometry.
and got x N of force.
and suppose, i have full geometry, what will be the pressing force?
will it be 4 times of first case or same?
@Nachiket Kadu @Prakash Pagadala @George P Johnson
I want to check pressing force required to insert ring into hub,
I have simulated 1/4th geometry.
and got x N of force.
and suppose, i have full geometry, what will be the pressing force?
will it be 4 times of first case or same?
Yes, we can sat that reaction forces are proportional to size of the component.
Hi,
Try these workarounds:
Hourglass seems to very high in the model.
For solid elements use Isolid-24 and if any shell elements are there use ishell-24 and N-5.
For the contact keep Istf to 4, so that minimum of master and slave will be calculated. Also give a minimum stiffness (Stmin-1000N/m). Plot the global contact energy also.
Ramp the load in 300 milliseconds so that the solution will be stable.
Once these changes are done, run the simulation and plot the hourglass energy for each part so that we can see which part is contributing more.
And finally make sure correct material type and parameters are used.
Which material is used for this?.
Thanks for the suggestions,
Bearing steel is used for ring, and aluminium is for housing.
You can see that houglass energy is still high. This model is going into hourglassing mode. What element formulation you are using? If you are using underintergrated elements, your hourglass energy should be as minimum as less than 5-10% of total energy.
@Ganesh Munge
Since the information available is very less to judge,
Can you refine the mesh at contact surface and check if that helps?