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It does not show units because the software does not track units. It is up to the user to keep track of the model units. In this case your displacement units will be the same units in which the model was run. For example if the model was built in mm the units of displacement will be mm.
Hi Ben
Thank you very much for your answer, I made the model in meters, but it is not logical that it is deformed 1326 m, because the longest length of the element is 10 meters, there what can I do? or is it wrong modeled?
Hi Ben
Thank you very much for your answer, I made the model in meters, but it is not logical that it is deformed 1326 m, because the longest length of the element is 10 meters, there what can I do? or is it wrong modeled?
Yes that definitely suggests a problem. Are you sure your units a consistent for all material properties and loads too? What does the animation look like? Have you done a normal modes analysis?
Yes that definitely suggests a problem. Are you sure your units a consistent for all material properties and loads too? What does the animation look like? Have you done a normal modes analysis?
Las unidades las trabajƩ como estƔn en la pƔgina, https://2022.help.altair.com/2022/hwsolvers/os/topics/solvers/os/unit_systems_consistent_system_r.htm
Las fuerzas las trabajĆ© como N y el modulo de Young y elasticidad en MPa, DeberĆa trabajar la fuerzas como MN o KN?
Las unidades las trabajƩ como estƔn en la pƔgina, https://2022.help.altair.com/2022/hwsolvers/os/topics/solvers/os/unit_systems_consistent_system_r.htm
Las fuerzas las trabajĆ© como N y el modulo de Young y elasticidad en MPa, DeberĆa trabajar la fuerzas como MN o KN?
if your model dimensions are in meters, then Youngs Modulus should be in Pa (not MPa) and force should be in N, if you have defined Youngs modulus in MPa then it is 1000000x too soft
i.e. if you have defined 210000 (2.1e5) in MPa for steel, it instead ought to be 210000000000 (2.1e11) in Pa
Because the analysis is linear, you should find the change will reduce your displacement by a factor of 1000000 too, so your max disp result should change from 1326m to 0.001326m (1.326mm)
if your model dimensions are in meters, then Youngs Modulus should be in Pa (not MPa) and force should be in N, if you have defined Youngs modulus in MPa then it is 1000000x too soft
i.e. if you have defined 210000 (2.1e5) in MPa for steel, it instead ought to be 210000000000 (2.1e11) in Pa
Because the analysis is linear, you should find the change will reduce your displacement by a factor of 1000000 too, so your max disp result should change from 1326m to 0.001326m (1.326mm)
Hi Paul
Thank you very much.
Las unidades las trabajƩ como estƔn en la pƔgina, https://2022.help.altair.com/2022/hwsolvers/os/topics/solvers/os/unit_systems_consistent_system_r.htm
Las fuerzas las trabajĆ© como N y el modulo de Young y elasticidad en MPa, DeberĆa trabajar la fuerzas como MN o KN?
if your model dimensions are in meters, then Youngs Modulus should be in Pa (not MPa) and force should be in N, if you have defined Youngs modulus in MPa then it is 1000000x too soft
i.e. if you have defined 210000 (2.1e5) in MPa for steel, it instead ought to be 210000000000 (2.1e11) in Pa
Because the analysis is linear, you should find the change will reduce your displacement by a factor of 1000000 too, so your max disp result should change from 1326m to 0.001326m (1.326mm)
It does not show units because the software does not track units. It is up to the user to keep track of the model units. In this case your displacement units will be the same units in which the model was run. For example if the model was built in mm the units of displacement will be mm.