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Hi Dung,
you can get more accurate result by having a tolerance condition inside a while loop. something like below:
%%
clc, clear
sum = 0;
sum_before = realmax;
tol = 1e-12; % tolerance value
i = 0;
while (abs(sum_before - sum) >= tol)
i= i+ 1;
sum_before = sum;
sum = sum + 1/(i^2);
end
%%
Hope this helps
Thanks,
Manoj kandukuri
Hi Dung,
you can try this:
clc, clear
Sum = 0;
for k=1:100000
Sum = 1/k^2 + Sum;
end