Find more posts tagged with
Sort by:
1 - 4 of
41
Hi,
Yes, but setting it to regular does nothing, that's what I tried to say
All attributes are regular by default when they are created, so it's not treated as an explicit type.
One could argue the operator should show regular as well, but then it would be harder to spot the interesting types like label, id, etc quickly. To me, there are arguments for both sides and this is the one that was chosen
Regards,
Marco
Yes, but setting it to regular does nothing, that's what I tried to say

All attributes are regular by default when they are created, so it's not treated as an explicit type.
One could argue the operator should show regular as well, but then it would be harder to spot the interesting types like label, id, etc quickly. To me, there are arguments for both sides and this is the one that was chosen

Regards,
Marco
Sort by:
1 - 1 of
11
Hi,
Yes, but setting it to regular does nothing, that's what I tried to say
All attributes are regular by default when they are created, so it's not treated as an explicit type.
One could argue the operator should show regular as well, but then it would be harder to spot the interesting types like label, id, etc quickly. To me, there are arguments for both sides and this is the one that was chosen
Regards,
Marco
Yes, but setting it to regular does nothing, that's what I tried to say

All attributes are regular by default when they are created, so it's not treated as an explicit type.
One could argue the operator should show regular as well, but then it would be harder to spot the interesting types like label, id, etc quickly. To me, there are arguments for both sides and this is the one that was chosen

Regards,
Marco
Looks pretty expected to me. Every attribute is regular, without needing to explicitly specify it. You only need to explicitly set the special roles like id, label, prediction, etc.
I guess the operator just highlights special roles
Regards,
Marco