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How to open or read tiff color image?

Hey there! I am very new to Rapidminer. When I try to open tiff color image and press the button "start the execution" I get this message :

Process failed access denied ("java.lang.RuntimePermission" "exitVM.0")

Exception: java.security.AccessControlException
Message: access denied ("java.lang.RuntimePermission" "exitVM.0")
Stack trace:
java.security.AccessControlContext.checkPermission(AccessControlContext.java:472)
java.security.AccessController.checkPermission(AccessController.java:884)
java.lang.SecurityManager.checkPermission(SecurityManager.java:549)
com.rapidminer.security.PluginSecurityManager.checkPermission(PluginSecurityManager.java:42)
java.lang.SecurityManager.checkExit(SecurityManager.java:761)
java.lang.Runtime.exit(Runtime.java:107)
java.lang.System.exit(System.java:971)
ij.IJ.getImage(IJ.java:1282)
cz.vutbr.feec.imageprocessing.op.readWrite.BaseReadImageOperator.readImage(BaseReadImageOperator.java:92)
cz.vutbr.feec.imageprocessing.op.readWrite.ReadColorImageOperator.doWork(ReadColorImageOperator.java:52)
com.rapidminer.operator.Operator.execute(Operator.java:1025)
com.rapidminer.operator.execution.SimpleUnitExecutor.execute(SimpleUnitExecutor.java:77)
com.rapidminer.operator.ExecutionUnit$2.run(ExecutionUnit.java:812)
com.rapidminer.operator.ExecutionUnit$2.run(ExecutionUnit.java:807)
java.security.AccessController.doPrivileged(Native Method)
com.rapidminer.operator.ExecutionUnit.execute(ExecutionUnit.java:807)
com.rapidminer.operator.OperatorChain.doWork(OperatorChain.java:428)
com.rapidminer.operator.Operator.execute(Operator.java:1025)
com.rapidminer.Process.execute(Process.java:1322)
com.rapidminer.Process.run(Process.java:1297)
com.rapidminer.Process.run(Process.java:1183)
com.rapidminer.Process.run(Process.java:1136)
com.rapidminer.Process.run(Process.java:1131)
com.rapidminer.Process.run(Process.java:1121)
com.rapidminer.gui.ProcessThread.run(ProcessThread.java:65)

Ι would appreciate the help.

Thank you

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Accepted answers

MartinLiebig

Hi,
which operator are you using? This looks like something you wrote on your own?
Best,
Martin

sgenzer

ah. Please note that the Image Mining extension is VERY OLD and full of bugs.

Scott

sgenzer

I would use an external API such as Google Cloud Vision.

rfuentealba

Hello, @icsdm417012

If you don't want to use an API (and there are plenty of reasons you might not want to do that), you can use the Execute Python operator (it's on the Python Scripting Extension). With the Anaconda Python Distribution, you can use matplotlib to read the TIFF file which conveniently obtains the values in a numpy array suitable to do your calculations.

This piece of code can be a good start. Like the old good Dijkstra says, I only have proven that this piece of code works but haven't executed it. I don't want to take the joy of experimenting from you, so maybe try it!

np.int_(data[1:,1:], index=data[1:,0], columns=data[0,1:])
    return df
import numpy
import pandas
import matplotlib.pyplot as plt

def rm_init(imgdata):
    my_image = plt.imread(tiff_file)
    df = pd.DataFrame(data=

All comments

MartinLiebig

Hi,
which operator are you using? This looks like something you wrote on your own?
Best,
Martin

icsdm417012

Thank you for answer me. I didn't write anything. I am using image Mining (IMMI). I tried to open jpeg color image and I didn't have any problem. But when I tried to open tiff color image I get this message. I have to mention that the tiff image is a satellite one.

Thank you again

sgenzer

ah. Please note that the Image Mining extension is VERY OLD and full of bugs.

Scott

icsdm417012

Thank you very much for answer me. Do you know any extension like image mining to suggest me?

Thank you again

sgenzer

I would use an external API such as Google Cloud Vision.

icsdm417012

Thank you very much

rfuentealba

np.int_(data[1:,1:], index=data[1:,0], columns=data[0,1:])
    return df
import numpy
import pandas
import matplotlib.pyplot as plt

def rm_init(imgdata):
    my_image = plt.imread(tiff_file)
    df = pd.DataFrame(data=

icsdm417012

Thank you for answer me. All this information is new to me. I will try to apply it. Thank you again