How to convert hex to decimal values in RM Studio ?

reedevtaneja

I have machine sensors data which I want to convert on the fly from hex to decimal so that I can use it further processing. Is there is a direct way or Reg Ex or function to do that in RM Studio ? I could see hex() and unhex() funcion in Radoop ( Generate Attributes) but not in Studio. Any help is appreciated.

 

Thanks

Reed

bhupendra_patil

Hello @reedevtaneja

 

There doesnot seem to be an operator to do that, however we can use the execute script operator to do this.and the script is very easy

Here is the script you will need and it is also in the attached example rmp process.

Please not that it changes all columns from hex to dec, so you will need to prefix it with  "select attributes" to pass only the desired ones.

Or depending on your use case, you cna hard code few things..

Hope this is helpful

 

 

ExampleSet exampleSet = operator.getInput(ExampleSet.class);

for (Attribute attribute : exampleSet.getAttributes()) {
    String name = attribute.getName();
    for (Example example : exampleSet) {
        //example[name] = example[name].toUpperCase();
		example[name] = Integer.parseInt(example[name].trim(), 16 );	

    }
}

return exampleSet;

reedevtaneja

Thanks BP, It was quick and helpful. 

bhupendra_patil

For similar use casez: This is example of Binary to Integers

 

ExampleSet exampleSet = operator.getInput(ExampleSet.class);

for (Attribute attribute : exampleSet.getAttributes()) {
    String name = attribute.getName();
    for (Example example : exampleSet) {
        //example[name] = example[name].toUpperCase();
		example[name] = Integer.parseInt(example[name].trim(), 2 );	

    }
}

return exampleSet;

bhupendra_patil

This is example of Hex to Binary

 

 

ExampleSet exampleSet = operator.getInput(ExampleSet.class);

for (Attribute attribute : exampleSet.getAttributes()) {
    String name = attribute.getName();
    for (Example example : exampleSet) {
        //example[name] = example[name].toUpperCase();
		int myint = Integer.parseInt(example[name].trim(), 16 );	
		example[name] = Integer.toBinaryString(myint)

    }
}

return exampleSet;

keildvol2

Ran into the same problem... any help is highly appreciated. Thank you!

EDIT: solved it in my case, maybe the following change to the script is helpful for others:

 

ExampleSet exampleSet = operator.getInput(ExampleSet.class);

for (Attribute attribute : exampleSet.getAttributes()) {
    String name = attribute.getName();
    for (Example example : exampleSet) {
          //example[name] = example[name].toUpperCase();
		example[name] = new BigInteger(example[name].trim(), 16);


    }
}

return exampleSet;

You could also try Long type first (instead of int) if your hex values are not that big.

 

Best regards

bhupendra_patil

Hello @reedevtaneja

 

There doesnot seem to be an operator to do that, however we can use the execute script operator to do this.and the script is very easy

Here is the script you will need and it is also in the attached example rmp process.

Please not that it changes all columns from hex to dec, so you will need to prefix it with  "select attributes" to pass only the desired ones.

Or depending on your use case, you cna hard code few things..

Hope this is helpful

 

 

ExampleSet exampleSet = operator.getInput(ExampleSet.class);

for (Attribute attribute : exampleSet.getAttributes()) {
    String name = attribute.getName();
    for (Example example : exampleSet) {
        //example[name] = example[name].toUpperCase();
		example[name] = Integer.parseInt(example[name].trim(), 16 );	

    }
}

return exampleSet;

reedevtaneja

Thanks BP, It was quick and helpful. 

bhupendra_patil

For similar use casez: This is example of Binary to Integers

 

ExampleSet exampleSet = operator.getInput(ExampleSet.class);

for (Attribute attribute : exampleSet.getAttributes()) {
    String name = attribute.getName();
    for (Example example : exampleSet) {
        //example[name] = example[name].toUpperCase();
		example[name] = Integer.parseInt(example[name].trim(), 2 );	

    }
}

return exampleSet;

bhupendra_patil

This is example of Hex to Binary

 

 

ExampleSet exampleSet = operator.getInput(ExampleSet.class);

for (Attribute attribute : exampleSet.getAttributes()) {
    String name = attribute.getName();
    for (Example example : exampleSet) {
        //example[name] = example[name].toUpperCase();
		int myint = Integer.parseInt(example[name].trim(), 16 );	
		example[name] = Integer.toBinaryString(myint)

    }
}

return exampleSet;

w_f_vandervegte

bhupendra_patil, I had the same question and I found your script here - thanks. I tried it in my similar process, after "select attributes" but it produced an error message: see attached screeshots. Any idea what may have gone wrong here?

keildvol2

Ran into the same problem... any help is highly appreciated. Thank you!

EDIT: solved it in my case, maybe the following change to the script is helpful for others:

 

ExampleSet exampleSet = operator.getInput(ExampleSet.class);

for (Attribute attribute : exampleSet.getAttributes()) {
    String name = attribute.getName();
    for (Example example : exampleSet) {
          //example[name] = example[name].toUpperCase();
		example[name] = new BigInteger(example[name].trim(), 16);


    }
}

return exampleSet;

You could also try Long type first (instead of int) if your hex values are not that big.

 

Best regards