How to convert a model into a process?

SheilaB

Hi!


I created a model, but I lost the process, which means I can´t see what I did, Is it possible for me to be able to see the process that is inside the model I have saved?

Thanks for your help!!!

Marco_Boeck

Hi,

I'm afraid not. To put it simply, a model is nothing more than a set of rules. It has no concept of a process with which it was created. It does however know how the data it was trained on looks like, if that is of any help. You can see it by writing the model in XML format to your disk like so:

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<process version="6.6.000-SNAPSHOT">
  <context>
    <input/>
    <output/>
    <macros/>
  </context>
  <operator activated="true" class="process" compatibility="6.6.000-SNAPSHOT" expanded="true" name="Process">
    <process expanded="true">
      <operator activated="true" class="retrieve" compatibility="6.6.000-SNAPSHOT" expanded="true" height="60" name="Retrieve Deals" width="90" x="45" y="30">
        <parameter key="repository_entry" value="//Samples/data/Deals"/>
      </operator>
      <operator activated="true" class="parallel_decision_tree" compatibility="6.6.000-SNAPSHOT" expanded="true" height="76" name="Decision Tree" width="90" x="246" y="30"/>
      <operator activated="true" class="write_model" compatibility="6.6.000-SNAPSHOT" expanded="true" height="60" name="Write Model" width="90" x="447" y="30">
        <parameter key="model_file" value="C:\Users\XYZ\Desktop\1.mod"/>
        <parameter key="output_type" value="XML"/>
      </operator>
      <connect from_op="Retrieve Deals" from_port="output" to_op="Decision Tree" to_port="training set"/>
      <connect from_op="Decision Tree" from_port="model" to_op="Write Model" to_port="input"/>
      <connect from_op="Write Model" from_port="through" to_port="result 1"/>
      <portSpacing port="source_input 1" spacing="0"/>
      <portSpacing port="sink_result 1" spacing="0"/>
      <portSpacing port="sink_result 2" spacing="0"/>
    </process>
  </operator>
</process>

Regards,
Marco