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Best way to evaluate weld?

Eskil Mellbin

Hi,

I would like how to ask how you do weld evaluation in Simsolid, as I am struggling with this currently.

For example, in my test case below there is a simple weld between two beams.

When extracting the forces from this weld I get the forces in the global coordinate system.

My experience with welds is using the Eurocode standard, getting the stresses in the weld, and then make sure the stresses are ok.

If I have understood simsolid correctly the forces of the welds can only be given in the global coordinate system, leading to the eurocode method being difficult.

What is your method of ensuring the strength of welds in your models, and what tips can you provide?

Best regards.

Eskil Mellbin

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SimSolid

v2022.0

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Gouthami Polina_22137

HI Eskil,

SimSolid's weld evaluation is implemented using Euro code3's 'Simplified method', which is based on comparing force per unit length with the allowables.

What you are looking at is a stress based 'Directional method', which we don't support today but will add it in the future.

Thanks,

Gouthami

Eskil Mellbin

HI Eskil,

SimSolid's weld evaluation is implemented using Euro code3's 'Simplified method', which is based on comparing force per unit length with the allowables.

What you are looking at is a stress based 'Directional method', which we don't support today but will add it in the future.

Thanks,

Gouthami

Hi Gouthami,

Thank you for your reply.

I just want to ensure I understand you correctly, as I haven't found a direct weld evaluation in the Simsolid software.

I extract the maximum force per unit length of the weld following the buttons shown in figure below.

This value (example 117.03N/mm) needs to be lower than the design weld resistance.

According to simplified method the design weld resistance is f_vw.d a*((f_u/(3)^0,5)/(B_u*Y_m2) (example of a 3mm weld in S235 material should be f_vw.d=3*((360/(3)^0,5)/(0,8*1,25)=623,54N/mm. With the example force above this should mean that the weld utilization is 1117,03/623,54 = 1,79, meaning a weld size of 6mm is required).

If my understanding is correct, is there a way to extract the maximum force magnitude per unit length for all welds in excel format as our product usually contains several hundreds of welds that should be evaluated in one form or another? As far as I have seen the forces exported from Reaction/contact force is the total forces and this might be too conservative.

Thank you again and best regards.

Eskil Mellbin

Gouthami Polina_22137

Hi Gouthami,

Thank you for your reply.

I just want to ensure I understand you correctly, as I haven't found a direct weld evaluation in the Simsolid software.

I extract the maximum force per unit length of the weld following the buttons shown in figure below.

This value (example 117.03N/mm) needs to be lower than the design weld resistance.

According to simplified method the design weld resistance is f_vw.d a*((f_u/(3)^0,5)/(B_u*Y_m2) (example of a 3mm weld in S235 material should be f_vw.d=3*((360/(3)^0,5)/(0,8*1,25)=623,54N/mm. With the example force above this should mean that the weld utilization is 1117,03/623,54 = 1,79, meaning a weld size of 6mm is required).

If my understanding is correct, is there a way to extract the maximum force magnitude per unit length for all welds in excel format as our product usually contains several hundreds of welds that should be evaluated in one form or another? As far as I have seen the forces exported from Reaction/contact force is the total forces and this might be too conservative.

Thank you again and best regards.

Eskil Mellbin

Hi Eskil,

We can only export total forces and not the max force for weld.

I have created an RFE for it. We will plan to add it in our next releases.

Thanks

Gouthami