plasticity calculation

Gerwin Neunteufel_21482
Gerwin Neunteufel_21482 New Altair Community Member
edited May 2023 in Community Q&A

Hello,
I'm currently investigating how plasticity is calculated in Inspire Cast.
For this I use the following PDF file:

 

Learn Modeling of elastoplastic Materials with Altair Compose

 

The exact code is written down in the file and the plasticity (linear isotropic hardening) can be calculated. If I use the material data from Inspire Cast (first figure), the result seems to be nearly ideal plastic. (second figure)

 

 

image

1.278e9 Pa-->1.278e3 MPa

 

image

Is there anything what I'm missing? 

Thank you

 

Best regards Gerwin

Answers

  • Daniel Diez Rodriguez
    Daniel Diez Rodriguez
    Altair Employee
    edited May 2023

    Hi Erwin,

    Sorry, I missed your question. Your rationale is correct. That is the curve that you would get although you have to take into account that our model is elasto-visco-plastic so the viscosity will change the result as it is a rate-dependent model.

  • Gerwin Neunteufel_21482
    Gerwin Neunteufel_21482 New Altair Community Member
    edited May 2023

    Dear Daniel Diez Rodrigeuez,

     

    thank you for your reply. I know that the viscosity is not taken into account.

    But for me, it seems that the slope is too low. 

     

    Regards Gerwin Neunteufel

  • Daniel Diez Rodriguez
    Daniel Diez Rodriguez
    Altair Employee
    edited May 2023

    Its true that it seems too low. The young modulus at room temperature is 1.28e11 so the linear coefficient is about 100 times smaller. (I think it is usually about 10% of the max young modulus). 

    The truth is that we do not have so much information about material data. If you have any reference that we could use to update the material database that'd be great. 

     

    FYI @Pablo Manuel Torne Fernandez 

  • Gerwin Neunteufel_21482
    Gerwin Neunteufel_21482 New Altair Community Member
    edited May 2023

    Dear Daniel Diez Rodriguez,

     

    I totally agree with you. I would make more sense, if the slope is 10 times smaller and not 100 times.

    But when looking at the material data, the hardening coefficient is always 100 times lower. 

     

    For example, Steel 1.4903:

    image

     

    Best regards Gerwin Neunteufel