Basic question regarding collision energy

Clemenslischka
Clemenslischka Altair Community Member
edited February 8 in Community Q&A

Hi all,

i study the effect of a fast rotating mixer on energy input. For this i look at all the collisions in an interval of 0.1s with my mixing tool. When i take the sum of all relative velocities between the particles and the mixing tool and calculate the kinetic energy gain from this, this should be equal to the mixing tool torque, shouldn't it? Further i can extract the total energy gain/loss during collision with the mixing tool. This value is also different from the one i calculated with the relative velocities of all particles. So I'm a bit confused right now.. What value should i look at if i want to assess how much energy is transfered during collisions with the mixing tool?

Thanks!

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Answers

  • Stefan Pantaleev_21979
    Stefan Pantaleev_21979
    Altair Employee
    edited February 8

    Hi Clemens,

    At steady state the agitator power should be equal to the collisional energy loss (integral of the work of friction and damping for all contacts).

    Best regards,

    Stefan

  • Clemenslischka
    Clemenslischka Altair Community Member
    edited February 8

    Hi Stefan,

    thanks for the reply. What about kinetic energy transfer from agitator to particle? In my mind the balance should be like: P_agitator = rel. collision velocity^2*mass_particle/2 + coll. energy loss (friction + damping).

    Total collision energy loss is also lower than power from torque in my data read-outs.

    Thanks!

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