Random Vibration PSD input

PSD value 0.1 G^2/Hz and want the results in MPa, simply convert it to (mm/s^2)^2/Hz =>  0.1*(9810*9810)=9623610 (mm/s^2)^2/Hz)

If you use mm and mass = tonnes (Mg), a psd in g^2/Hz then you stress should be in MPa^2/Hz, disp in mm^2/Hz, accel in (mm/s^2)/Hz 

Hi Rahul,

Thank you for your response.

PSD value 0.1 G^2/Hz and want the results in MPa, simply convert it to (mm/s^2)^2/Hz =>  0.1*(9810*9810)=9623610 (mm/s^2)^2/Hz)

when i have value in 0.1 G^2/Hz,  i don't have to convert the values to (mm/s^2)^2/Hz since i follow the stranded table which i mentioned below.

If you use mm and mass = tonnes (Mg), a psd in g^2/Hz then you stress should be in MPa^2/Hz, disp in mm^2/Hz, accel in (mm/s^2)/Hz.

Yes when my model is in mm, mass in tonnes, and psd in g^2/Hz, then what should i do to get results, Stress in MPa, Disp in mm?

Let me put a table,

I need output to be displacement in mm, stress in MPa.

when the psd input changes, what conversion factor to be used to get output, displacement in mm, stress in MPa.

Correct me if i am wrong,

G^2/Hz=(m/s^2)^2/Hz

g^2/Hz=(mm/s^2)^2/Hz

Regards,

Kishore.

Please refer attached pdf for random response analysis which should clear most of your doubts.

Thank you for the document provided Rahul.

Attached document clarified most of the doubts, still need small clarification as shown below.

And I have attached PPT of my understanding, Kindly review.

Thank you in advance,

Regards,

Kishore.

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Please refer attached pdf for random response analysis which should clear most of your doubts.

Hi, thank you for sharing this document. I was wondering, if we can access the rest of it?