Differences between analytic and Radioss solutions in modal transient dynamic analysis
Hey,
we have a mass applied to a spring, which is clamped on the other side. At the mass we apply a Cosinus load [ F*COS(OMEGA*t) ]
F = 500 N
OMEGA = 1 1/s
t = 0 - 8 s [DT 0.01]
Now we do a modal transient dynamic analysis and look at the history of displacements with the help of Hyperview.
The screenshot shows the result in HyperView.
Now the problem is, that the analytic results are not the same.
Our sping has a rate (k) of 500 N/m and the apllied mass has a weigth (m) of 10 kg.
So we calculate with the following equations:
omega=sqrt(k/m)
set-up ratio: eta=OMEGA/omega
magnification function: V=sqrt(1/(1-eta^2)^2)
The whole system is undamped.
The equation for the displacement is:
x(t)=(F/k)*V*cos(OMEGA*t)
for the maximum amplitude: cos(OMEGA*t)=1.
Answers
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Hi,
can you confirm if the force applied is a dynamic load?
Assuming the mass is in Kgs, the modelled CONM2 is 10Kgs (which is 98.1 N ~100N) which is a static load and a dynamic load factor of 500 will make the dynamic load or force to 100*500= 5*E4.
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Hi,
the red triangle is a DAREA load with a value of -500N. In the collector Tabled there is the cosine profile of this force.
In the Load Collector TLoad we combine the DAREA Force with the cosine profile to a dynamic load, which excites the mass at the end of the spring.But the problem is, that we don't get equal solutions with Hyperworks and the manual calculation.
Thanks and regards.
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Hi,
Sorry for a late response,
could you please let me the location at which you are looking at the results?
is it the excited point?
also, the OMEGA used in equation is it 11/s or 1/s? (1 1/s is what furnished in your previous post)
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Hi,
no problem.
We are looking at the results at the point, where the mass is applied, because its the only point of the two which can be displaced. Yes, Its the excited point.
The OMEGA is 1/s --> 1 s^(-1)
Thanks and regards
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Hi,
The omega= sqrt(K/m) holds good for angular frequency, it is not what are you interested, I guess. So it should be the dynamic analysis is natural frequency (rad/time)
to the omega should be (2* pi / T = 2 * Pi * f) where f= 1 / 2*pi ( (sqrt (K/M)).
could you please check the above?
Also, could you give us any reference of the calculation (formula) from which you calculated the displacement?
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Hi,
the equation seems to be for steady state, can you run the same analysis with frequency response, instead of transient response?
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Yes, the max displacement is recorded as you specified.
Please go ahead and make a FRA and let us know your findings
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