Particle Positioning

Hi Johnson

The particle position always refers to the center of mass of the particle. So the position you are looking for is
X = (L/2)*(1+cos 60)
Z = (L/2)*(sin 60)

Hope this helps.

Thanks,
Jerrin Job

Thank you, Jerrin, for the information. the Formula actually gave me something close as seen below.

But I actually wanted the particles to be tangential to each other as seen in the image, which I obtained manually by just changing the numbers

my question now is, how did you come about the formula below you shared earlier, and are there any resources you can recommend for me to really understand this particle position

X = (L/2)*(1+cos 60)

Z = (L/2)*(sin 60)

Hi Johnson

My assumption was that all your particles are of the same length. In case of different lengths, it would be
X = (L_particle0 / 2) + ((L_particle1 / 2) * cos 60)
Z = (L_particle1 / 2) * (sin 60)

This comes from basic trigonometry of lines in space.

Hope this helps.

Thanks,
Jerrin Job

Thank you, Jerrin