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Getting Twist Angle on Shaft Under Torsion

Hi Everyone,

I'm running a simulation where the model is a shaft under pure torsion loading. My goal is just to validate the result of my FEA and see if it matches my calculation. I'm using a tetramesh model and even thoughthe meshing is coarse I kind of get similar value to my hand calculation on the shear stress part.

The problem comes when I tried to generate the twist angle of the shaft, for some reason the value for that is really small compared to my calculation. Does anyone experience this? What do I need to do to fix this?

Attached is the file that I'm using.

Best,

Ariq

3D_torsion_2.hm

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HyperMesh

v2020.0

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Rogerio Nakano_21179

Based on the geometry (D=3.84, and length=18)

, the material (Poison=0.3 and Young Modulus = 1,060,000)

and load (torque = 1,000) the value of angle is estimated as:

Angle is about 0.002rad

Is this the estimated value you are getting?

Regards

Achmad Zufar

Hi

Based on the geometry (D=3.84, and length=18)

, the material (Poison=0.3 and Young Modulus = 1,060,000)

and load (torque = 1,000) the value of angle is estimated as:

Angle is about 0.002rad

Is this the estimated value you are getting?

Regards

Yes. Unfortunately in my model it did not generate any twist angle. It says 0 for it. Do you know what might have happened?

Rogerio Nakano_21179

Yes. Unfortunately in my model it did not generate any twist angle. It says 0 for it. Do you know what might have happened?

if you need the angle of shaft twist , what you could do is

- in HyperView create a local cylindrical coordinate system that is centered in the face that you are applying torque, with the z-axis aligned to the shaft axis.

- So that x -> radial disp (r) and y-> angular disp (theta)

- when contouring, you select the displacement result, y-component. Also select the user defined coordinate system and contour.

- That will contour the angular displacement of the nodes relative to the local cylindrical coordinate system

- you can query the external diameter nodes and check the rotation of this nodes, relative to the origin of local coordinate system, that is the center of rotation you selected.

I hope that is helpful

Regards

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