An exclusive raffle opportunity for active members like you! Complete your profile, answer questions and get your first accepted badge to enter the raffle.
I m having problem to understand GRAV card image of load collector.
please help
Hi,
Â
Please check the image below (Global coordinate system)
<?xml version="1.0" encoding="UTF-8"?>
How does a computer can know to which component in an assembly acceleration needs to be applied.
As we don't give any input to GRAV of component or assembly
iashishsarode
Gravity is applied as a field on the entire model.Â
thank you for helping me to understand.
My plan is to apply the gravity on the y-z plane in the direction of the bisector formed by the y and z Vector.
How would i do that?
By having the input:
g: 5 units
n1: 0
n2: 1
n3: 1
Would that mean the value 5 units would be applied simultaneously in the y-direction as well as in the z-direction or would it mean that 5 units would be applied in the direction of the bisector of z and y?
My plan is to apply the gravity on the y-z plane in the direction of the bisector formed by the y and z Vector. Â How would i do that? By having the input: g: 5 units n1: 0 n2: 1 n3: 1 Would that mean the value 5 units would be applied simultaneously in the y-direction as well as in the z-direction or would it mean that 5 units would be applied in the direction of the bisector of z and y? Â Â Â
G is the total magnitude and N1, N2 and N3 will give you the direction only.
If you want to compute individually, you can create multiple GRAV cards and combine them with LOADADD card.
I.e: create 2GX, create 1GZ and then combine them with LOADADD card.
Or also create unit GRAV in each direction, and use the S1 multipliers to get the 2G, 1G, etc..